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__Boats and Streams
Formula__

__Boats and Streams Formula__

All the students who are searching the Boats and Streams
Formula they have finally reached at right place because in this article mostly
all

the types of questions are covered by the team members of the portal for
all those participants who are ready to become master in the Boats and Streams
chapter. We all know that quantitative aptitude section possess Boats and
Streams questions definitely. Applicants who don’t know the basics of the
problem solving they face problem in this topic. Here we are providing you
Boats and stream formula and problem solving shortcut tricks under one roof.
These tricks and solved questions will be useful in your preparation of
competitive government exams.
In those exams where Boats and streams topic covers it is
said that at least 2-3 questions will also be there in the Aptitude section. These
types of questions are generally asked in most of the aptitude tests for
companies like Infosys, TCS, HCL, all government job exams etc. Advantage to
ask this question on boats and streams is to search the capacity of the mind to
the appliers who are willing to appoint in a special organization. There are
only two fundamental concepts following in such questions and students can
solve several questions with these concepts. Hey guys learn all the given Shortcut
Tips & Tricks to Solving Problem from the below portion of the article. All
the best!!

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__Boats and Streams Formula Shortcut Tips to
Solving Problem__

__Boats and Streams Formula Shortcut Tips to Solving Problem__

**1)**Given a boat travels downstream with speed

**d**km/hr and it travels with speed

**u**km/hr upstream. Find the speed of stream and speed of boat in still water?

**: Let speed of boat in still water is b km/hr and speed of stream is s km/hr.**

__Solution__
Then b + s = d and b – s = u

Solving the 2 equations we get,

b = (d + u)/2

s = (d – u)/2

**2)**A man can row a boat, certain distance downstream in

**td**hours and returns the same distance upstream in

**tu**hours. If the speed of stream is

**s**km/h, then the speed of boat in still water is?

**: We know distance = speed * time**

__Solution__
Let the speed of boat be b km/hr

__Case downstream__:

d = (b + s) * td

__Case upstream__:

d = (b - s) * tu

=> (b + s) / (b - s) = tu / td

**b = [(tu + td) / (tu - td)] * s**

**3)**A man can row in still water at

**b**km/h. In a stream flowing at

**s**km/h, if it takes him t hours to row to a place and come back, then the distance between two places,

**d**is given by

**Downstream:**Let the time taken to go downstream be td

d = (b + s) * td

**Upstream: Let the time taken to go upstream be tu**

d = (b - s) * tu

td + tu = t

[d / (b + s)] + [d / (b - s)] = t

So, d = t * [(b

^{2}- s^{2}) / 2b]
OR

**Short trick: d = [t * (Speed to go downstream) * (Speed to go upstream)]/[2 * Speed of boat or man in still water]**

**4)**A man can row in still water at

**b**km/h. In a stream flowing at

**s**km/h, if it takes t hours more in upstream than to go downstream for the same distance, then the distance

**d**is given by

**Time taken to go upstream = t + Time taken to go downstream**

__Solution__:
(d / (b - s)) = t + (d / (b + s))

=> d [ 2s / (b

^{2}- s^{2}] = t
So, d = t * [(b

^{2}- s^{2}) / 2s]
OR

**Short trick: d = [t * (Speed to go downstream) * (Speed to go upstream)] / [2 * Speed of still water]**

**If speed of boat or swimmer is x km/h and the speed of stream is y km/h then,**

Speed of boat downstream = (x + y) km/h

**When speed of boat is given then it means speed in the still water, unless it is stated otherwise.**

__Important Points of Boats and Streams Formula__:**-**

__Some Basic Formulas__
Speed of boat in still water is

= ½ (Downstream Speed + Upstream Speed)

Speed of stream is

= ½ (Downstream Speed – Upstream Speed)

**: Short tricks with formula for boats and streams is given as you expected,**

__Boats and streams formulas__

__Downstream / Upstream__:
Direction along the stream is called Downstream.

Direction against the stream is called upstream.

If the speed in the still water is x km / hr and the speed
of the stream is y km / hr then,

Speed downstream = (x + y) km / hr.

Speed upstream = (x – y) km / hr.

If the speed downstream is u km / hr and the speed
upstream is v km / hr then,

Speed in still water = (1 / 2) (a + b) km / hr.

Rate of stream = (1 / 2) (a – b) km / hr.

__Some Important Solved Questions__

__Types of Questions asked in Previous Exam by SSC:__

**Type 1**: When the distance covered by boat in downstream is same as the distance covered by boat upstream. The speed of boat in still water is x and speed of stream is y then ratio of time taken in going upstream and downstream is,

__Short Trick__:**Time taken in upstream**:

**Time taken in Downstream**= (x+y)/(x-y)

**1)**A man can row a boat @ 9 km ph in still water. He takes double the time to move upstream than to move the downstream – the same distance. Find the speed of the stream?

According to Question and formula given above:

Let the downward time = 1 hour and so the upward time = 2
hours.

1/9+s = 2/9-s (Since distance is the same)

18 + 2 s = 9 – s (By cross multiplication)

18 – 9 = s + 2 s

9 = 3 s

Hence s or Speed of stream = 9/3 =

**3 km ph Answer.****OR**

Simply

b + s = 2(b –s)

b + s = 2b – 2s

s + 2s = 2b –b

**OR**

b = 3s or 9 = 3s (b = 9 is given) =

**3 km ph Answer****2)**A boat runs at 20 km ph along the stream and 10 km ph against the stream. Find the ratio of speed of the boat in still water to that of the speed of the stream?

ATQ (According to Question) and formula given above:

Speed of Boat = ½ (20 + 10) = 15 km ph.

Speed of Stream = ½ (20 – 10) = 5 km ph.

Ratio: 15:5 =

**3:1 Answer.****3)**Find the speed of the stream when a boat takes 5 hours to travel 60 kms downstream at a rate of 10 kms per hour in still water?

According to Question and formula given above:

Speed b + s = 60/5 = 12 km ph

Speed b = 10 km ph

So speed is = 12-10 =

**2 km ph Answer.****4)**If a man rows 6 km downstream in 3 hours and 2 km upstream in 2 hours then how long will he take to cover 9 kms in stationary (still) water?

According to Question and formula given above:

Speed of Boat in still waters = ½ (6/3 + 2/2) = ½ (2 + 1) =
1.5 km ph

Time taken for 9 kms = 9/1.5 =

**6 hours Answer****5)**A boat covers a certain distance in one hour downstream with the speed of 10 km ph in still water and the speed of current is 4 km ph. Then find out the distance travelled?

According to Question and formula given above:

Distance = Speed x Time = 1 x (10+4) =

**14 kms**.**: Dear candidates to get the complete details of other such formulas stay tuned with ejobhub.**

__Reminder____Take a Look on Below Table__

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